Comments on: Derive relation F = ma from Newton 2nd Law of Motion

By: Darshan s

Darshan s — Fri, 21 Oct 2022 02:19:28 +0000

In reply to Riya Patil. its to good we can easily get 3 marks in examination

By: Anthony Matovu

Anthony Matovu — Sun, 29 May 2022 12:42:08 +0000

Take care when you equate Newtonian linear distance d and the circumferential distance which is pi x d (diameter). This holds on knowing that Einstein’s energy is radiated energy and hence involves circular geometry. Otherwise you cannot derive Einstein’s infamous energy formula from Newton’s second law of motion!!!

By: r praveen kumar

r praveen kumar — Thu, 07 Mar 2019 14:46:04 +0000

easy steps

By: Arghyadeep Malas

Arghyadeep Malas — Sun, 03 Mar 2019 03:33:26 +0000

I cannot understood it properly…….
What is the meaning of-dp & dt??!!!

By: Joel

Joel — Wed, 16 Jan 2019 03:31:55 +0000

In reply to Hari. A Newton is a kgm/s^2. So a kgm/s^2/kg leaves a unit of m/s^2. You just have to break the Newton down into its components to cancel the kg and get the acceleration in typical units.

By: Sreejith Mohan

Sreejith Mohan — Wed, 14 Nov 2018 02:05:01 +0000

I have been lurking though the textbook and guides to understand the derivation !
This finally helped me ! Thanks a lot

By: Hari

Hari — Wed, 24 Oct 2018 06:54:55 +0000

From F=ma, if we derive for acceleration it is, a=F/m…As per this the unit of acceleration would become Newton/Kilogram (N/kg)…
But the actual unit of acceleration is m/s^2…
I am confused…

By: NAVIN(Indian student of 11th grade)

NAVIN(Indian student of 11th grade) — Tue, 07 Aug 2018 15:47:55 +0000

it would be clearer if u mentioned p=mv and v/t=a and thus ma arises out,

anyways good work and thanks.

By: Riya Patil

Riya Patil — Sat, 14 Jul 2018 02:20:40 +0000

Hey it’s too good i clearly understood the law