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	Comments on: Relation between polarization vector (P), displacement (D) and electric field (E)	</title>
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	<lastBuildDate>Wed, 24 Apr 2013 11:38:26 +0000</lastBuildDate>
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		By: aaditya		</title>
		<link>https://winnerscience.com/relation-between-polarization-vector-p-displacement-d-and-electric-field-e/#comment-256</link>

		<dc:creator><![CDATA[aaditya]]></dc:creator>
		<pubDate>Wed, 24 Apr 2013 11:38:26 +0000</pubDate>
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					<description><![CDATA[dear sir,

will u plz explain me about electric field due to polarisation 

Ep= free charge/(k€*A)

where k is relative permitivity and € is permitivity of vaccume

or k*€= $ 

where $ is the permitivity of medium.

now since Ep is field induced within dielectric then why you have used € in the term Ep???

means you have asumed both external and induced field in vaccume? but in vaccume polarisation of wot will happen?

means electric polarization is zero

plz explain me why have you taken € (permitivity of vaccume) in both Ep and external applied field???



my mail id is

p.aaditya@hotmail.com]]></description>
			<content:encoded><![CDATA[<p>dear sir,</p>
<p>will u plz explain me about electric field due to polarisation </p>
<p>Ep= free charge/(k€*A)</p>
<p>where k is relative permitivity and € is permitivity of vaccume</p>
<p>or k*€= $ </p>
<p>where $ is the permitivity of medium.</p>
<p>now since Ep is field induced within dielectric then why you have used € in the term Ep???</p>
<p>means you have asumed both external and induced field in vaccume? but in vaccume polarisation of wot will happen?</p>
<p>means electric polarization is zero</p>
<p>plz explain me why have you taken € (permitivity of vaccume) in both Ep and external applied field???</p>
<p>my mail id is</p>
<p><a href="mailto:p.aaditya@hotmail.com">p.aaditya@hotmail.com</a></p>
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