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		<title>Waves between parallel planes</title>
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		<pubDate>Sun, 27 Jan 2013 07:38:02 +0000</pubDate>
				<category><![CDATA[Electromagnetism]]></category>
		<category><![CDATA[derivation wave equation parallel planes]]></category>
		<category><![CDATA[derivation waves between parallel planes]]></category>
		<category><![CDATA[derivation waves parallel planes]]></category>
		<category><![CDATA[field equations parallel planes]]></category>
		<category><![CDATA[guided waves]]></category>
		<category><![CDATA[parallel planes]]></category>
		<category><![CDATA[wave equations parallel planes]]></category>
		<category><![CDATA[waves guided through parallel planes]]></category>
		<guid isPermaLink="false">https://winnerscience.com/?p=3320</guid>

					<description><![CDATA[<p>Let us discuss how waves propagate through parallel planes and derive the necessary relation of transverse electric and magnetic waves: Assumptions : (a)  Pair of parallel planes are perfectly conducting. (b)  Separation between the planes is ‘a’ meter in x – direction. (c)  Space between planes is perfect dielectric (σ</p>
<p>The post <a href="https://winnerscience.com/waves-between-parallel-planes/">Waves between parallel planes</a> first appeared on <a href="https://winnerscience.com">Winner Science</a>.</p>]]></description>
										<content:encoded><![CDATA[<p style="text-align: justify;">Let us discuss how waves propagate through parallel planes and derive the necessary relation of transverse electric and magnetic waves:</p>
<p style="text-align: justify;"><b>Assumptions :</b></p>
<p style="text-align: justify;">(a)  Pair of parallel planes are perfectly conducting.</p>
<p style="text-align: justify;">(b)  Separation between the planes is ‘a’ meter in x – direction.</p>
<p style="text-align: justify;">(c)  Space between planes is perfect dielectric (σ = 0) of permittivity ε and permeability μ.</p>
<p style="text-align: justify;">(d)  Planes are of infinite extent in the y and z direction.<span id="more-3320"></span></p>
<p style="text-align: justify;">(e)  As the plane is extended to infinity in the y – direction there are no boundary conditions to be met in this direction, therefore field is uniform in the y- direction  i.e. derivative with respect to y is zero (d/dy =0)</p>
<p style="text-align: justify;">(f)     Direction of propagation of wave is along z-direction, therefore the variation of all the field component in the z-direction is expressed as e<sup>-y</sup><sub>g</sub><sup>z</sup></p>
<p style="text-align: justify;">Where y<sub>g</sub> = a<sub>g</sub> + jb<sub>g</sub></p>
<p style="text-align: justify;">Here y<sub>g</sub>is  propagation constant and it is not equal to y(y<sub>g </sub>¹ y). In special case of uniform plane waves, y<sub>g</sub> reduces to y.</p>
<p style="text-align: justify;">a<sub>g</sub> is attenuation constant, and</p>
<p style="text-align: justify;">b<sub>g</sub> is phase constant.</p>
<p style="text-align: justify;">(g)  In time varying form, the field variation is expressed as</p>
<p style="text-align: justify;">                        e<sup>jwt</sup> e<sup>-y</sup><sub>g</sub><sup>z</sup> = e<sup> (jwt &#8211; y</sup><sub>g</sub><sup>z)</sup></p>
<p style="text-align: justify;"><sup>                                </sup>e<sup>(jwt – (a</sup><sub>g </sub>+ <sup>j</sup>b<sub>g</sub><sup>)z)</sup></p>
<p style="text-align: justify;">If there is no attenuation, a<sub>g</sub> = 0 then field variation is expressed as</p>
<p style="text-align: justify;"><sup>                                </sup>e<sup>jwt</sup> <sup>&#8211; j</sup>b<sub>g</sub><sup>z</sup> = e<sup> j(wt  &#8211; </sup>b<sub>g</sub><sup>z)</sup></p>
<p style="text-align: justify;"><b>Boundary Conditions :</b></p>
<p style="text-align: justify;">In order to determine the electromagnetic field configuration between parallel planes, Maxwell’s field equation are solved with the following boundary condition :</p>
<p style="text-align: justify;">(I)                 Electric field must terminate normally on the conductor, that is, tangential component of electric field must be zero.</p>
<p style="text-align: justify;">            E<sub>tan</sub>  = 0</p>
<p style="text-align: justify;">(II)              Magnetic field must lie tangentially along the wall surface, that is, the normal component of magnetic field must be zero.</p>
<p style="text-align: justify;">            H<sub>nor</sub> = 0</p>
<p style="text-align: justify;"><b><i>Derivation of field equations :</i></b></p>
<p style="text-align: justify;">In general, Maxwell’s equations (Modified Ampere’s Circuital law and Faraday’s law of em induction) in non-conducting region (σ = 0) between the planes are</p>
<p style="text-align: justify;">                        Ñ x <b>H</b> = jw<b>εE</b>   (Modified Ampere’s circuital law)           (1)</p>
<p style="text-align: justify;">                        Ñ x <b>E</b> = jwμ<b>H</b>  (Faraday’s law of em iduction)                 (2)</p>
<p style="text-align: justify;">Expanding equation (1) in rectangular coordinates, we get</p>
<p style="text-align: justify;">                          <b>a<sub>x </sub>        a<sub>y                            </sub>a<sub>z</sub></b></p>
<p style="text-align: justify;">Ñ x <b>H</b> = d/dx      d/dy            d/dz    = jw<b>ε</b> (E<sub>x</sub>a<sub>x</sub> + E<sub>y</sub>a<sub>y </sub>+ E<sub>z</sub>a<sub>z</sub>)</p>
<p style="text-align: justify;">            <b>H</b><sub>X<b>           </b></sub><b>H</b><sub>Y           </sub><b>H</b><sub>Z</sub></p>
<p style="text-align: justify;"><b>            a</b><sub>x</sub>    d<b>H</b><sub>z</sub>/dg – d<b>H</b><sub>y</sub>/dz    &#8211; <b>a</b><sub>y</sub>    d<b>H</b><sub>z</sub>/dx– d<b>H</b><sub>x</sub>/dz    + <b>a</b><sub>y</sub>    d<b>H</b><sub>y</sub>/dx– d<b>H</b><sub>x</sub>/dg</p>
<p style="text-align: justify;"><b>            = j</b>wε<b>E<sub>x</sub>a</b><sub>x </sub>+<b>j</b>wε<b>E<sub>y</sub>a</b><sub>y</sub> + <b>j</b>wε<b>E<sub>z</sub>a</b><sub>z</sub></p>
<p style="text-align: justify;">Comparing the respective components on both sides, we get</p>
<p style="text-align: justify;">            dH<sub>z</sub>/dg  &#8211;  dH<sub>y</sub>/dz  = <b>j</b>wε<b>E<sub>x</sub></b></p>
<p style="text-align: justify;">            dH<sub>x</sub>/dz  &#8211;  dH<sub>z</sub>/dx  = <b>j</b>wε<b>E<sub>y</sub></b></p>
<p style="text-align: justify;">            dH<sub>y</sub>/dx  &#8211;  dH<sub>x</sub>/dg = <b>j</b>wε<b>E<sub>z                                                                      </sub>(3)</b></p>
<p style="text-align: justify;">Similarly expanding equation (2) and equating respective components on both sides, we get</p>
<p style="text-align: justify;">            d<b>E</b><sub>z</sub>/dg &#8211;  d<b>E</b><sub>y</sub>/dz  = <b>j</b>wμ<b>H<sub>x</sub></b></p>
<p style="text-align: justify;">            d<b>E</b><sub>x</sub>/dz  &#8211;  d<b>E</b><sub>z</sub>/dx  = <b>j</b>wμ<b>H<sub>y</sub></b></p>
<p style="text-align: justify;">            d<b>E</b><sub>y</sub>/dx  &#8211;  d<b>E</b><sub>x</sub>/dg  = <b>j</b>wμ<b>H<sub>z                                                                                    </sub>(4)</b></p>
<p style="text-align: justify;">From assumption (f), as the direction of propagation is along z-direction, the variation of field components can be expressed as</p>
<p style="text-align: justify;">                        <b>H</b><sub>x</sub> = <b>H</b><sub>x0</sub> e<sup>-y</sup><sub>g</sub><sup>z</sup></p>
<p style="text-align: justify;">            Thus     d<b>H</b><sub>x</sub> /dz =<sup>-y</sup><sub>g</sub>H<sub>x0</sub> e<sup>-y</sup><sub>g</sub><sup>z</sup></p>
<p style="text-align: justify;">            Or        d<b>H</b><sub>x</sub> /dz = -g<sub>g</sub><b>H</b><sub>x                                                                             </sub>(5a)</p>
<p style="text-align: justify;">Similarly          dH<sub>y</sub>/dz = -g<sub>g</sub>H<sub>y                                                                               </sub>(5b)</p>
<p style="text-align: justify;">                        dE<sub>x</sub>/dz = -g<sub>g</sub>E<sub>x                                                                                                </sub>(5c)</p>
<p style="text-align: justify;">and                 dE<sub>y</sub>/dz = -g<sub>g</sub>E<sub>y                                                                                                </sub>(5d)</p>
<p style="text-align: justify;">also from assumption (e), d/dy = 0</p>
<p style="text-align: justify;">            dH<sub>z</sub>/dg &#8211;  dH<sub>x</sub>/dg = d<b>E</b><sub>z</sub>/dg = d<b>E</b><sub>x</sub>/dg = 0                              (5e)</p>
<p style="text-align: justify;">By substituting equations 5a, b and e,  we have</p>
<p style="text-align: justify;">            g<sub>g</sub>H<sub>y</sub> = <b>j</b>wε<b>E<sub>x                                                                                                    </sub></b>(6a)</p>
<p style="text-align: justify;">            -g<sub>g</sub>H<sub>x</sub> &#8211; dH<sub>z</sub>/dx = <b>j</b>wε<b>E<sub>y                                                                              </sub></b>(6b)</p>
<p style="text-align: justify;"><b>            </b>d<b>H<sub>y</sub></b>/dx = <b>j</b>wε<b>E<sub>z                                                                                             </sub></b>(6c)<b><sub>                                       </sub></b></p>
<p style="text-align: justify;">Similarly by substituting equations 5c, d and e in equation 4, we have</p>
<p style="text-align: justify;">            g<sub>g</sub>E<sub>y</sub> = &#8211;<b> j</b>wμ<b>H<sub>x                                                                                                                </sub></b>(7a)</p>
<p style="text-align: justify;"><b><sub>&#8211;</sub></b>g<sub>g</sub>E<sub>x</sub>-dE<sub>z</sub>/dx = -jwμ<b>H<sub>y                                                                                                               </sub></b>(7b)</p>
<p style="text-align: justify;">dE<sub>y</sub>/dx = &#8211;<b> j</b>wμ<b>H<sub>z                                                                                                         </sub></b>(7c)</p>
<p style="text-align: justify;"><b>Now use equations 6a and 7b</b></p>
<p style="text-align: justify;">From equation 6a</p>
<p style="text-align: justify;">Ex = g<sub>g</sub>H<sub>y</sub>/jwε</p>
<p style="text-align: justify;">Putting value of Ex in equation 7(b), we have</p>
<p style="text-align: justify;">g<sup>2</sup><sub>g</sub>H<sub>y</sub>/jwε + dEz/dx = jwμ<b>H<sub>y</sub></b></p>
<p style="text-align: justify;"><b> </b></p>
<p style="text-align: justify;">            dE<sub>z</sub>/dx =( <b>j</b>wμ – g<sup>2</sup>g/<b>j</b>wε)H<sub>y</sub></p>
<p style="text-align: justify;"><b>j</b>wε (dE<sub>z</sub>/dx) = (-w<sup>2</sup>με &#8211; g<sup>2</sup>g) H<sub>y</sub></p>
<p style="text-align: justify;"> <b>j</b>wε (dE<sub>z</sub>/dx) = -H<sub>y</sub>(g<sup>2</sup>g+ H<sub>y</sub> w<sup>2</sup>με)</p>
<p style="text-align: justify;">            = &#8211; H<sub>y</sub>K<sup>2</sup>g</p>
<p style="text-align: justify;">            K<sup>2</sup>g = g<sup>2</sup>g + w<sup>2</sup>με</p>
<p style="text-align: justify;">            H<sub>y</sub> = &#8211;<b> j</b>wε/ K<sup>2</sup>g   dE<sub>z</sub>/dx                                                        (8a)</p>
<p style="text-align: justify;"><b>Again use equations 6a and 7b</b></p>
<p style="text-align: justify;">From equation</p>
<p style="text-align: justify;">                        H<sub>y</sub> = 1/<b> j</b>wμ ( dE<sub>z</sub>/dx  + g<sub>g</sub>E<sub>x</sub>)</p>
<p style="text-align: justify;">Substituting value of H<sub>y</sub> in equation , we have</p>
<p style="text-align: justify;">            g<sub>g</sub>/<b> j</b>wμ ( dE<sub>z</sub>/dx  + g<sup>2</sup>gEx/jwμ )= jwE<sub>x</sub></p>
<p style="text-align: justify;">            g<sub>g</sub>/<b> j</b>wμ ( dE<sub>z</sub>/dx ) (jwε- g2g/<b> j</b>wμ)E<sub>x</sub></p>
<p style="text-align: justify;">            g<sub>g</sub>(dE<sub>z</sub>/d<sub>x</sub>) = (-w<sup>2</sup> με &#8211; g2g) E<sub>x</sub></p>
<p style="text-align: justify;"><sub>                &#8211;</sub> Y<sub>g</sub>(dE<sub>z</sub>/d<sub>x</sub>) = E<sub>x</sub>K<sup>2</sup><sub>g</sub></p>
<p style="text-align: justify;">            K<sup>2</sup><sub>g</sub> = g<sup>2</sup>g + w<sup>2</sup> με</p>
<p style="text-align: justify;">            E<sub>x</sub> = (gg/ K<sup>2</sup><sub>g</sub>) dE<sub>z</sub>/dx                                                 (8b)</p>
<p style="text-align: justify;"><b>Similarly by using and solving equations 6b and 7a, we get</b></p>
<p style="text-align: justify;">            H<sub>x</sub> = (-gg/ K<sup>2</sup><sub>g</sub>) dH<sub>z</sub>/dx                                               8c</p>
<p style="text-align: justify;">and     E<sub>y</sub>= (jwμ/ K<sup>2</sup><sub>g</sub>) dH<sub>z</sub>/dx                                                           8d</p>
<p style="text-align: justify;">where            K<sup>2</sup><sub>g</sub> = g<sup>2</sup><sub>g</sub> + w<sup>2</sup>με</p>
<p style="text-align: justify;">Equations 8(a,b,c and d) represent the equations of plane waves propagating in +z direction varying sinusoidally between the infinite parallel planes.</p>
<p style="text-align: justify;">In equation, the components of electric and magnetic fields strengths are expressed in terms of E<sub>z</sub> and H<sub>z</sub>.</p>
<p style="text-align: justify;">If E<sub>z</sub> = 0 and  H<sub>z</sub> = 0, all the components will vanish, therefore it is observed that there must be a z component of either E or H i.e. comonent along the direction of  propagation.</p>
<p style="text-align: justify;">Therefore, the propagating waves in parallel plane guide are classified into following types according to whether E<sub>z</sub> or H<sub>z </sub>exists :</p>
<ol style="text-align: justify;">
<li>Transverse Electric (TE) Waves or H Waves (E<sub>z</sub> = 0, H<sub>z</sub> ¹ 0)</li>
<li>Transverse Magnetic (TM) Waves or E Waves (H<sub>z</sub> = 0, E<sub>z</sub> ¹ 0)</li>
</ol>
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