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	<title>what is Simultaneity in relativity | Winner Science</title>
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		<title>Simultaneity in relativity</title>
		<link>https://winnerscience.com/simultaneity-in-relativity/</link>
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		<dc:creator><![CDATA[amsh]]></dc:creator>
		<pubDate>Thu, 06 Oct 2011 07:50:40 +0000</pubDate>
				<category><![CDATA[Relativity]]></category>
		<category><![CDATA[define Simultaneity in relativity]]></category>
		<category><![CDATA[derivation Simultaneity in relativity]]></category>
		<category><![CDATA[relativity of Simultaneity]]></category>
		<category><![CDATA[relativity of Simultaneity derivation]]></category>
		<category><![CDATA[Simultaneity in relativity]]></category>
		<category><![CDATA[what is relativity of Simultaneity]]></category>
		<category><![CDATA[what is Simultaneity in relativity]]></category>
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					<description><![CDATA[<p>Let there are two inertial frames of references S and S’. S is the stationary frame of reference and S’ is the moving frame of reference. At time t=t’=0 that is in the start, they are at the same position that is Observers O and O’ coincides. After that S’</p>
<p>The post <a href="https://winnerscience.com/simultaneity-in-relativity/">Simultaneity in relativity</a> first appeared on <a href="https://winnerscience.com">Winner Science</a>.</p>]]></description>
										<content:encoded><![CDATA[<p style="text-align: justify;">Let there are two inertial frames of references S and S’. S is the stationary frame of reference and S’ is the moving frame of reference. At time t=t’=0 that is in the start, they are at the same position that is Observers O and O’ coincides. After that S’ frame starts moving with a uniform velocity v along x axis.<a rel="attachment wp-att-2378" href="https://winnerscience.com/relativity/simultaneity-in-relativity/attachment/fig-simultaneity-2/"><a rel="attachment wp-att-2379" href="https://winnerscience.com/relativity/simultaneity-in-relativity/attachment/fig-simultaneity-3/"><img fetchpriority="high" decoding="async" class="size-full wp-image-2379 alignnone" title="fig-simultaneity" src="https://winnerscience.com/wp-content/uploads/2011/10/fig-simultaneity2.png" alt="" width="540" height="250" /></a></a>Let two events in frame S occur simultaneously at positions P1 and P2. The coordinates of the P1 will be (x1,y1,z1,t1) and of P2 will be (x2,y2,z2,t2). The events will be simultaneous (occur at the same time) according to the observer in frame S. Therefore</p>
<p style="text-align: justify;">t1 = t2                                                              (1)<span id="more-2376"></span></p>
<p style="text-align: justify;">The question arises here will the event be simultaneous from frame S’? Let us discuss it?</p>
<p style="text-align: justify;">From Lorentz transformation equations of time:</p>
<p style="text-align: justify;">t’1 = (t1 – x1v/c<sup>2</sup>)/(√1 – v<sup>2</sup>/c<sup>2</sup>)                          (2)</p>
<p style="text-align: justify;">and t’2 = (t2 – x2v/c<sup>2</sup>)/(√1 – v<sup>2</sup>/c<sup>2</sup>)                   (3)</p>
<p style="text-align: justify;">Subtracting equation (2) from equation (3), we get</p>
<p style="text-align: justify;">t’2 – t’1 = (t2 – x2v/c<sup>2</sup>)/(√1 – v<sup>2</sup>/c<sup>2</sup>) &#8211; (t1 – x1v/c<sup>2</sup>)/(√1 – v<sup>2</sup>/c<sup>2</sup>)</p>
<p style="text-align: justify;">or t’2 – t’1 = (t2 – t1)/ )/(√1 – v<sup>2</sup>/c<sup>2</sup>) &#8211; v/c<sup>2</sup>(x2 – x1)/(√1 – v<sup>2</sup>/c<sup>2</sup>)</p>
<p style="text-align: justify;">Put equation (1) in above equation, we get</p>
<p style="text-align: justify;">t’2 – t’1 = &#8211; v/c<sup>2</sup>(x2 – x1)/(√1 – v<sup>2</sup>/c<sup>2</sup>)        (4)</p>
<p style="text-align: justify;">As the two events occur at different positions, that is</p>
<p style="text-align: justify;">x2 ≠x1</p>
<p style="text-align: justify;">Therefore L.H.S of equation (4) will not be zero, thus<a rel="attachment wp-att-2377" href="https://winnerscience.com/relativity/simultaneity-in-relativity/attachment/fig-simultaneity/"><br />
</a></p>
<p style="text-align: justify;">t’2 – t’1 ≠ 0</p>
<p style="text-align: justify;">or t’1 ≠ t’2</p>
<p style="text-align: justify;">It proves that the same events will not be simultaneous from frame S’, that is it will not appear to occur at the same time from S’.</p>
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