Comments on: Time dilation in relativity derivation

By: amsh

amsh — Sat, 05 Mar 2022 17:09:18 +0000

In reply to Michael Cleveland. But the square root symbol is there.

By: Michael Cleveland

Michael Cleveland — Sat, 19 Feb 2022 13:44:17 +0000

In reply to Michael Cleveland. In offering my correction, I simply cut and paste your formula and moved the square root to the correct position in the formula. The superscripts did not survive the cut and paste, so to clarify, it is only the square root symbol that is out of place.

By: Michael Cleveland

Michael Cleveland — Sat, 19 Feb 2022 04:27:59 +0000

Sorry, there was a bad edit in my reply. It should have read “there is no other medium that would permit a moving mass to reach speeds at which time dilation would come into play.

By: Michael Cleveland

Michael Cleveland — Sat, 19 Feb 2022 04:25:39 +0000

In reply to Kasim Muflahi. The simple answer might be that there is no other medium that would permit velocities of mass to reach speeds at which time dilation would come into play. Light can travel through transparent solids, transparent gasses or a vacuum. Obviously solids are out, and any gas with sufficient density to significantly affect the speed of light would be as unapproachable at relativistic speed as the solid, so the question becomes irrelevant.

By: Michael Cleveland

Michael Cleveland — Sat, 19 Feb 2022 04:19:35 +0000

Your time dilation formula is incorrectly written. I should read t = t’/√(1 – v2/c2). The square root symbol was misplaced.

By: amsh

amsh — Wed, 13 Apr 2016 15:53:15 +0000

In reply to Kasim Muflahi. In the derivation, the c is assumed to be constant, that is is free space or vacuum.

By: Kasim Muflahi

Kasim Muflahi — Sat, 09 Apr 2016 17:20:35 +0000

You only get time dilation if you assume c to be constant; otherwise t is invariant. It cannot be independently proved that c is constant. If c is constant in all frames of reference, why do we have to measure it in a vacuum? Shouldn’t it be constant in all media?

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