Relativistic energy-momentum relation derivation
Relativistic energy momentum relation:
From Einstein mass energy relation
E = mc2 (1)
Also from variation of mass with velocity relation
m = m0/(1 – v2/c2)1/2 (2)
Where m0 is the rest mass of the object
Put value of m in equation (1) and then square both sides, we get
E2= m02c4/(1 – v2/c2) (3)
As momentum is given by
p = mv
Put equation (2) and square
p2 = m02v2/(1 – v2/c2)
Multiply both sides by c2
p2c2 = m02v2 c2/(1 – v2/c2) (4)
Subtract equation (4) from (3) and solve, we get
E2 – p2c2 = m02c4
Or E = (p2c2 + m02c4)
This is Relativistic energy momentum relation