Transverse electric waves
DEFINITION TRANSVERSE ELECTRIC (TE) WAVES OR H WAVES IN PARALLEL PLANES:
In the case, the component of electric field vector E lies in the plane transverse to the direction of propagation that is there is no component of E along the direction of propagation where as a component of magnetic field vector H lies along the direction of propagation.
Derivation of transverse electric waves in parallel planes:
As the direction of propagation is assumed as z-direction, therefore
Ez = 0 and Hz is not equal to 0
Now by substituting Ez = 0 in equation (8) of article “waves between parallel planes”, we get
Ex= 0 and Hy = 0 and
Ey not equals to 0 , Hx not equals to 0
Now write wave equations for free space in terms of E
Ñ2E =g2gE
= -w2μεE (because g2g = (jwμ) (σ + jwε) As σ =0(from assumption (c) of article “waves between parallel planes” => g2g =-w2με)
Or d2E/dx2 + d2E/dy2 + d2E/dz2 = -w2μεE
For the y component, the wave equation will become
d2Ey/dx2 + d2Ey/dg 2 + d2Ey/dz2 = -w2μεEy
also dEg/dg = 0 [using assumption (e)]
and Eg = Eg0 e– ggz [using assumption (f)] of article “waves between parallel planes”
Thus d2Eg/dz2 = g2Eg2gEg2gEg
By substituting above values of dEg/dg and d2Ey/dz2 in wave equation, we get
d2Eg/dx2 + g2gEg= -w2μεEg
or d2Eg/dx2 = -(g2g + w2με) Eg
or d2Eg/dx2 = –K2g Eg ..(9)
where K2g = g2g + w2με
as Eg = Eg0 e– ggz ..(10(a))
thus d2Eg/dx2 = d2Eg0 e– ggz/dx2 ..(10(b))
by substituting equation(10) in equation (9) , wave equation becomes
d2Eg0/ dx2 = K2g Eg0
The above equation is a standard differential equation of simple harmonic motion and its solution can be written in the form
Eg0 = A1 sin Kgx + A2cos Kgx
Or Eg = (A1 sin Kgx + A2 cos Kgx) e– ggz ..(11)
Where A1 and A2 are arbitrary constants.
A1 and A2 can be determined with the help of following boundary conditions :
Etan = 0 at the surface of conductor
This implies that
Ey = 0 at x = 0
Ey = 0 at x = a
Thus apply boundary condition
That Ey = 0 at x = 0
So equation (11)will become
0 = (A1 sin Kg0 + A2 cos Kg0) e– ggz
Thus equation (11) reduces to
Ey = A1 sin Kgxe– ggz ..(12)
Now apply boundary condition
That Ey = 0 at x = a in equation, we get
0 = A1 sin Kgae– ggz
Or sinKga = 0 as A1¹ 0
Or Kga = mπ
Or Kg = mπ/a, wher m = 1,2,3
(If m = 0, all field components vanish. Its a special case and will be discussed later)
. equation (12)becomes
. . Ey = A1 sin (mπ/a)e– ggz
Ey = A1 sin (mπ/a)e–jbgz (. . gg = jbg if αg = 0) ..(13(a))
Put equation (13 a)in (8 d of article “waves between parallel planes”)and integrate
A1 sin (mπx/a)e– ggz = jwμ/ K2g dHz/dx dx
Hz = A1 K2g e– ggz /jwμ sin(mπx/a)/dx
= – A1m2π2/a2 e– ggz/ jwμ cos (mπx/a)/ mπ where K2g = m2π2/a2
Hz =- A1 mπ cos (mπx/a) e– ggz/ jwμ
or Hz =- A1 mπ cos (mπx/a) e– ggz/ jwμ (gg = jbg) ..(13(b))
Differentiate (13(b))w.r.t. x
dHz/dx = A1m2π2 sin (mπx/a) e– ggz/ jwμa2
Substitute above equation in equation
Hx=- gg / K2g A1 m2π2/ jwμa2 sin (mπx/a) e– ggz
Hx=- gg m2π2/a2 A1 m2π2/jwμa2 sin (mπx/a) e– ggz
Hx=- gg A1 /jwμ sin (mπx/a) e– ggz
Hx=- bg A1 /wμ sin (mπx/a) e– ggz ( gg = jbg) ..(13(c))
Equation (13(a)), (b), (c)) represent the expressions for field components for TE waves. Each value of m in equations (13) represent a particular field configuration and the wave associated with integer m is designated as TEm wave. The lowest order mode that can exist in this case is TE1 mode.
This is the definition, discussion and derivation of transverse electric (TE) waves between parallel planes or plates.